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but it still kinda achieves the exact same thing.
Not really. If you have another reference to the original array, and you use this method to 'empty' it - stuff is going to break as the other reference will still contain the unemptied array
Thanks for the support Nathan.
I've never met that kind of error but I'll try it in the future. Thanks for the assistance though.
var a = [1, 2, 3] var b = a; a = []; console.log(b); // [1, 2, 3]
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but it still kinda achieves the exact same thing.
Not really. If you have another reference to the original array, and you use this method to 'empty' it - stuff is going to break as the other reference will still contain the unemptied array
Thanks for the support Nathan.
I've never met that kind of error but I'll try it in the future. Thanks for the assistance though.
I've never met that kind of error but I'll try it in the future. Thanks for the assistance though.
var a = [1, 2, 3]
var b = a;
a = [];
console.log(b); // [1, 2, 3]