Your filter function only need return true or false, and as @adam_cyclones points out, you should really only check the unique values in the merged array (no point checking the same numbers more than once):
function diffArray(arr1, arr2) { let merge = [...new Set([...arr1, ...arr2])] return merge.filter(function(num) { return arr1.indexOf(num) === -1 || arr2.indexOf(num) === -1 }) }
or, shorter:
const diffArray = (arr1, arr2) => [...new Set([...arr1, ...arr2])].filter( num => arr1.indexOf(num) === -1 || arr2.indexOf(num) === -1 )
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Your filter function only need return true or false, and as @adam_cyclones points out, you should really only check the unique values in the merged array (no point checking the same numbers more than once):
or, shorter: