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Discussion on: [Challenge] 🐝 FizzBuzz without if/else

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Replies for: py3, oneliner because ofc fizzbuzz = lambda x: "Fizz"*(x and not x%3)+"Buzz"*(x and not x%5) or str(x) print([fizzbuzz(n) for n in range(16)])

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John Selbie •

If it were up to me, I'd declare this the winner.