Python challenge_15

All equal

Define a function named all_equal()
that takes a list and checks whether all elements in
the list are the same.

For example:
calling all_equal([1, 1, 1]) should return True.

Challenge URI

My solution

def all_equal(equal_list):

    result = all(element == equal_list[0] for element in equal_list)

    if (result):
        return True
    else:
        return False
print(all_equal([1, 1, 1]))

Aother solution

def all_equal(items):
    for item1 in items:
        for item2 in items:
            if item1 != item2:
                return False
    return True

All the best to you.

Comments

[benny]

Nice challenge. May I add another solution using set()? I like to use it combined with equality operator:

def all_equal(nums):
    return len(set(nums)) == 1

Have a good one! :)

[Mahmoud EL-kariouny]

Nice solution 👌 Benny

You are the best

[Cyzy666]

Could be wrong, but does this work? If everything in the list is identical, then the first number (or any number in the list, for that matter) must represent all numbers in the list.

def all_equal(series):
    return series.count(series[0]) == len(series)