If you think that's too short to work - here's the proof:
First, let's define that as a function: getMark←{md←10|m←(+⌿÷⍴)⍵ ⋄ ((1+60 70 80 90 101⍸m)⊃'FDCBA'),' -+'[1+(md≠5)×1+(,5)⍸md]}
And now you can simply do getMark 64 55 92
C- getMark 99 89 93
A- getMark 33 99 95
C+
And if you still don't believe me, try it here or there! ;-)
(These online solutions use the symbol ≢ instead of ⍴ - they are equivalent in this case, but ≢ renders incorrectly on dev.to. There's also an issue with another APL-Character: ⍸ - if someone from the dev-team would contact me, I'd love to help sorting that out...)
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APL (I'm using Dyalog APL):
{md←10|m←(+⌿÷⍴)⍵ ⋄ ((1+60 70 80 90 101⍸m)⊃'FDCBA'),' -+'[1+(md≠5)×1+(,5)⍸md]}If you think that's too short to work - here's the proof:
First, let's define that as a function:
getMark←{md←10|m←(+⌿÷⍴)⍵ ⋄ ((1+60 70 80 90 101⍸m)⊃'FDCBA'),' -+'[1+(md≠5)×1+(,5)⍸md]}And now you can simply do
getMark 64 55 92C-
getMark 99 89 93A-
getMark 33 99 95C+
And if you still don't believe me, try it here or there! ;-)
(These online solutions use the symbol ≢ instead of ⍴ - they are equivalent in this case, but ≢ renders incorrectly on dev.to. There's also an issue with another APL-Character: ⍸ - if someone from the dev-team would contact me, I'd love to help sorting that out...)