Probably not a very efficient way to do it, but it works:
def strongest_number(interval): counter = interval[0] numbers = [] while counter <= interval[1]: if counter % 2 == 0: numbers.append(counter) counter += 1 strengths = {} for i in range(len(numbers)): result = numbers[i] count = 0 while result % 2 == 0: result = result / 2 count += 1 strengths[i] = count largest = 0 k = "" for key in strengths: if strengths[key] > largest: largest = strengths[key] k = key return numbers[k]
Are you sure you want to hide this comment? It will become hidden in your post, but will still be visible via the comment's permalink.
Hide child comments as well
Confirm
For further actions, you may consider blocking this person and/or reporting abuse
We're a place where coders share, stay up-to-date and grow their careers.
Probably not a very efficient way to do it, but it works: