Discussion on: [Challenge] 🐝 FizzBuzz without if/else

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Replies for: const fb = n => [...Array(n).keys()].map(n => n+1).map(n => (n % 5 === 0 && n % 3 === 0) && 'FizzBuzz' || (n % 5 ...

An alternative using recursion instead of native methods.

const fb = n =>
    n && (
        fb(n - 1)
        + (
                (!(n % 3 && n % 5) && 'FizzBuzz')
                || (!(n % 3) && 'Fizz')
                || (!(n % 5) && 'Buzz')
                || n
        ) + ' '
    );

console.log(fb(30))