USECASE
The aim of this page📝 is to explain how to print the last field in a line of text using bash, when the number of fields varies. I was planning to use cut but learned that I need awk at the end.
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Tools Needed:
awk,cut. - Goal: Print the last field of varying field count lines.
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Why:
cutis limited to fixed fields. -
Solution: Use
awkfor dynamic field handling.
Steps
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Understanding
cut: Handles fixed number of fields. -
Limitation:
cutcan't handle varying fields. -
Solution Overview: Use
awkto overcomecutlimitations. -
Basic
awkSyntax:awk '{print $NF}'. -
Example:
echo "one two three four" | awk '{print $NF}'. -
Explanation:
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echo "one two three four": Simulates text input. -
awk '{print $NF}': Prints last field.
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- File Input: Handle files line by line.
- File Example:
cat filename.txt | awk '{print $NF}'
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Explanation:
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cat filename.txt: Reads file content. -
awk '{print $NF}': Prints last field of each line.
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- Practical Application: Use in scripts for dynamic data processing.
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