const curry = (fn, ...args) => args.length >= fn.length ? fn(...args) : (...x) => curry(fn, ...args, ...x); const uncurry = (fn) => (...args) => args.reduce((fn, arg) => fn(arg), fn); const mul = (a, b) => a * b; const curriedMul = curry(mul); const mulBySeven = curriedMul(7); const uncurriedMul = uncurry(curriedMul); console.log(curriedMul(2)(3)); // 6 console.log(mulBySeven(11)); // 77 console.log(uncurriedMul(5, 7)); // 35
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Discussion on: Currying in JS 🤠
Replies for: CHALLENGE Write a function that curries a function. It should take a function as an argument, and return the curried version. NEXT LEVE...
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