Exception handling tricky question

4)
{
int a[]= {10,20,30,40};
for(int i=0;i<=a.length;i++)
{
try {
int b=0;
System.out.println(a[i]/b);
}

        catch(ArithmeticException e)
        {
            System.out.println("invalid number");

        }
        catch(Exception E)
        {
            System.out.println(E.getMessage());
        }

    }
}

 }

2)
{
int a=10;

    try {
        int b=0;
        System.out.println(a/b);
    }
    catch(Exception e)
    {
        System.out.println("invalid number");
    }

}

 }

3)
{
int a=10;

    try {
        int b=5;
        System.out.println(a/b);
    }
    finally
    {
        System.out.println("invalid");
    }


}

 }

4)try {
int b=0;
System.out.println(a/b);
}
catch(Exception e)
{
System.out.println("invalid number");
}
finally
{
System.out.println(" Enter valid number");
}
5)It is already handled by the catch block for Exception

6)compilation problem
7)compilation problem
8)compilation problem
9)compilation problem
10)compilation problem
11)compilation problem
12)compilation problem
13)compilation problem
14){
int a[]= {10,20,30,40};

    for(int i=0;i<=a.length;i++)

    {
        try {
            int b=0;
            System.out.println(a[i]/b);
        }

        catch(RuntimeException e)
        {
            System.out.println("invalid number");


        }

        catch(Exception E)
        {
            System.out.println(E.getMessage());
        }

15)compilation problem