REVERSE INTEGER -LEETCODE SOLUTION C++

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123
Output: 321
Example 2:

Input: x = -123
Output: -321
Example 3:

Input: x = 120
Output: 21

Constraints:

-231 <= x <= 231 - 1

SOLUTION C++

class Solution {
public:
    int reverse(int x) {
        int num = x;
        long int rev = 0;
        while(num != 0){
            int digit = num%10;
            rev = 10*rev + digit;
            if(rev > INT_MAX)return 0;//1
            if(rev < INT_MIN)return 0;//2
            num/=10;
        }
        return (int)rev;
    }
};

LINE 1 AND 2 used due to if their is any negative values exist