Discussion on: [Challenge] 🐝 FizzBuzz without if/else

[Russ Edwards]

Here's a solution to the challenge in JavaScript...

function fizzBuzz (n) {
    let i = 1
    let fbline = []
    let output = []
    let count = 0
    while (i <= n) {
        fbline = [i, i, i, "Fizz", i, "Buzz", "Fizz", i, i, "Fizz", "Buzz", i, "Fizz", i, i, "FizzBuzz"]
        output.push("" + fbline[(i+count) % 16])
        i++
        count = Math.floor(i / 16)
    }
    console.log(output)
}
fizzBuzz(90)

Here's a repl.it where you can run this.