Discussion on: Daily Challenge #194 - Spread Number

[Sagiv ben giat]

JavaScript:

const spreadNumber = n => [...Array(n).keys()]

[Daan Wilmer]

I think you have an off-by-one error: spreadNumber(2) gives [0, 1] instead of [1, 2]. Nice and concise, though!

[Sagiv ben giat]

Thanks. I didnt notice its zero based

[Jeroen Cornelissen]

That creates an Array from 0 to n not from 1 to n ;-)

const spreadNumber = n => Array(n).fill(0).map((_, i) => i+1);

[Sagiv ben giat]

Yeah, i didnt notice its not zero based

[Matt Ellen-Tsivintzeli]

Another way:

const spreadNumber = n => Array.from({length:n}).map((_, i) => i+1);