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Discussion on: Daily Challenge #35 - Find the Outlier

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Replies for: I believe this would fail if the outlier is even and the rest are an odd number of odd numbers. The examples all have an even number of odd numbers...

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tanguyandreani profile image
Tanguy Andreani •

It seems that I can’t make it right and as simple as it was. So I’ll stick with this solution:

def findOutlier numbers
  if numbers.first(3).count(&:even?) > 1
    numbers.find(&:odd?)
  else
    numbers.find(&:even?)
  end
end

puts findOutlier([2, 4, 0, 100, 4, 11, 2602, 36])
puts findOutlier([160, 3, 1719, 19, 11, 13, -21, 33])
puts findOutlier([160, 3, 1719, 19, 11, 13, -21])
puts findOutlier([4, 8, 15, 16, 24, 42])
puts findOutlier([16, 6, 40, 66, 68, 28])
puts findOutlier([3,3])