Hi,
Thank you for your kind comment!
For this part that you are referring to:
Thus, if the first statement in a constructor does not explicitly invoke another constructor with this() or super(), Java implicitly inserts the call super(); that is, it calls the superclass constructor with no arguments. If the superclass does not have a constructor that takes no arguments, this implicit invocation causes a compilation error.
I think I was trying to say that as opposed to something being done explicitly by the author of the code (writing and calling super()):
Java "implicitly" calls super() and this "implicit" invocation causes a compilation error.
I agree that perhaps "implicit" isn't the best way to describe it here but I am glad that you get the point:)
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Hi,
Thank you for your kind comment!
For this part that you are referring to:
I think I was trying to say that as opposed to something being done explicitly by the author of the code (writing and calling
super()):super()and this "implicit" invocation causes a compilation error.I agree that perhaps "implicit" isn't the best way to describe it here but I am glad that you get the point:)