Discussion on: Daily Challenge #189 - Convert Number into Reversed Array

[Vidit Sarkar]

C++

vector<int> convertNtA(long number){
    vector<int> numDigits;
    if(number == 0) // if number is zero then return vector with only 0
        return vector<int>({0});

    while(number > 0){
        numDigits.push_back(number%10);
        number /= 10;
    }
    return numDigits;
}

Python one liner

def convertNtA(number):
    return list(map(int,str(number)[::-1]))
print(convertNtA(123456))

convertNtA = lambda number : list(map(int,str(number)[::-1]))
print(convertNtA(123456))