Here is a recursive approach using Python
def pattern(number, end=1): res = ''.join([str(i) for i in range(int(number), end-1, -1)]) if end >= int(number): return res return res + '\n' + pattern(number, end+1)
One liner for the above
pattern = lambda number, end=1 : ''.join([str(i) for i in range(int(number), end-1, -1)]) + ('' if end >= int(number) else '\n' + pattern(number, end+1))
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Here is a recursive approach using Python
One liner for the above