This is a little snippet writeup of code that will find the average color of an image of RGBA8 pixels (32bits per pixel, 8 bits per channel) by utilizing the psadbw
(_mm_sad_epu8
) instruction to accumulate the sum of each individual channel into a (very overflowsafe)64bit accumulator.
Inspired by the "SIMDized sum of all bytes in the array" writeup by Wojciech MuΕa.
The usual method to get the statistical average of each color channel in an image is pretty trivial:
 Load in a pixel
 Unpack the individual color channels
 Sum the channel values into a an accumulator
 When you've summed them all, divide these sums by the number of total pixels
 Interleave these averages into a new color value
Something like this:
std::uint32_t AverageColorRGBA8(
std::uint32_t Pixels[],
std::size_t Count
)
{
std::uint64_t RedSum, GreenSum, BlueSum, AlphaSum;
RedSum = GreenSum = BlueSum = AlphaSum = 0;
for( std::size_t i = 0; i < Count; ++i )
{
const std::uint32_t& CurColor = Pixels[i];
AlphaSum += static_cast<std::uint8_t>( CurColor >> 24 );
BlueSum += static_cast<std::uint8_t>( CurColor >> 16 );
GreenSum += static_cast<std::uint8_t>( CurColor >> 8 );
RedSum += static_cast<std::uint8_t>( CurColor >> 0 );
}
RedSum /= Count;
GreenSum /= Count;
BlueSum /= Count;
AlphaSum /= Count;
return
(static_cast<std::uint32_t>( (std::uint8_t)AlphaSum ) << 24 ) 
(static_cast<std::uint32_t>( (std::uint8_t) BlueSum ) << 16 ) 
(static_cast<std::uint32_t>( (std::uint8_t)GreenSum ) << 8 ) 
(static_cast<std::uint32_t>( (std::uint8_t) RedSum ) << 0 );
}
This is a pretty serial way to do it. Pick up a pixel, unpack it, add it to a sum.
Each of these unpacks and sums are pretty independent of each other can be parallelized with some SIMD trickery to do these unpacks and sums in chunks of 4, 8, even 16 pixels at once in parallel.
There is no dedicated instruction for a horizontal sum of 8bit elements within a vector register in any of the x86 SIMD variations.
The closest tautology is an instruction that gets the Sum of Absolute Differences of 8bit elements within 64bit lanes, and then horizontally adds these 8bit differences into the lower 16bits of the 64bit lane. This is basically computing the manhatten distance between two vectors of eight 8bit elements.
AD(A,B) = ABS(A  B) # Absolute difference
X = ( 1, 2, 3, 4, 5, 6, 7, 8) # 8 byte vectors
Y = ( 8, 9,10,11,12,13,14,15)
# Sum of absolute differences
SAD(X,Y) =
# Absolute difference of each of the pairs of 8bit elements
AD(X[0],Y[0]) + AD(X[1],Y[1]) + AD(X[2],Y[2]) + AD(X[3],Y[3]) +
AD(X[4],Y[4]) + AD(X[5],Y[5]) + AD(X[6],Y[6]) + AD(X[7],Y[7])
=
ABS( 1  8 ) + ABS( 2  9 ) + ABS( 3  10 ) + ABS( 4  11 ) +
ABS( 5  12 ) + ABS( 6  13 ) + ABS( 7  14 ) + ABS( 8  15 )
=
ABS( 7 ) + ABS( 7 ) + ABS( 7 ) + ABS( 7 ) +
ABS( 7 ) + ABS( 7 ) + ABS( 7 ) + ABS( 7 )
# Horizontally sum all these differences into a 16bit value
= 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7
= 56
psadbw
may seem like a pretty niche instruction at first. You're probably wondering why such a specific series of operations is implemented as an official x86 instruction but it has had plenty of usage since the original SSE days to aid in blockbased motion estimation for video encoding.
The trick here is recognizing that the absolute difference between an unsigned number and zero, is just the unsigned number again. The sum of the absolute difference between a vector of unsigned values and vector0 is a way to extract just the horizontaladdition step of SAD for this particular use.
(A is unsigned)
AD(A,B) = ABS(A  0) = A
X = ( 1, 2, 3, 4, 5, 6, 7, 8) # 8 byte vectors
Y = ( 0, 0, 0, 0, 0, 0, 0, 0)
SAD(X,Y) =
AD(X[0],0) + AD(X[1],0) + AD(X[2],0) + AD(X[3],0) +
AD(X[4],0) + AD(X[5],0) + AD(X[6],0) + AD(X[7],0)
=
X[0] + X[1] + X[2] + X[3] + X[4] + X[5] + X[6] + X[7]
=
1 + 2 + 3 + 4 + 5 + 6 + 7
= 28
This kind of utilizaton of psadbw
will allow a vector of 8 consecutive bytes to be horizontally summed into the low 16bits of a 64bit lane, and this 16bit value can then be directly added to a larger 64bit accumulator. With this, a chunk of RGBA color values can be loaded into a vector, unpacked so that all their R,G,B,A bytes are grouped into 64bit lanes, psadbw
these 64bit lanes to get 16bit sums, and then accumulate these sums into a 64bit accumulator to later get their average.
Usually, taking the average of a large amount of values can cause some worry for overflow. With instructions like psadbw
that operate on 64bit lanes, it lends itself to the usage of 64bit accumulators which are very resistant to overflow.
An individual channel would need 2^64 / 2^8 == 72057594037927936
pixels (almost 69 billion megapixels) with a value of 0xFF
for that color channel to overflow its 64bit accumulator.
Pretty resistant I'd say.
An SSE vectorregister is 128 bits, it will be able to hold two 64bit accumulators per vectorregister so one SSE register can be used to accumulate the sum of GreenRed
values and another vectorregister for the AlphaBlue
sums.
The main loop would look something like this:
 Load in a chunk of 4 32bit pixels into a 128bit register
ABGRABGRABGRABGR
 Shuffle the 8bit channels within the vector so that the upper 64bits of the register has one channel, and the lower 64bits has another.
 There is a bit of "waste" as you only have four bytes of a particular channel and 8bytes within a lane. These values can be set to zero by passing a shuffleindex with the upper bit set when using
_mm_shuffle_epi8
(A value such as1
will getpshufb
to write0
). This way these bytes will not effect the sum. 
0G0G0G0G0R0R0R0R
or0A0A0A0A0B0B0B0B

0000GGGG0000RRRR
or0000AAAA0000BBBB
works too  Any permutation in particular works so long as the unused elements do not effect the horizontal sum and are 0
 There is a bit of "waste" as you only have four bytes of a particular channel and 8bytes within a lane. These values can be set to zero by passing a shuffleindex with the upper bit set when using

_mm_sad_epu
the vector, getting two 16bit sums within each of the 64bit lanes, add this to the 64bit accumulators
0000Ξ£G160000Ξ£R16
or0000Ξ£A160000Ξ£B16
16bit sums, within the upper and lower 64bit halfs of the 128bit register

A psadbw
accelerated pixelsumming loop that handles four pixels at a time would look something like this:
//  64bit Red Sum  64bit Green Sum 
__m128i RedGreenSum64 = _mm_setzero_si128();
//  64bit Blue Sum  64bit Alpha Sum 
__m128i BlueAlphaSum64 = _mm_setzero_si128();
// 4 pixels at a time! (SSE)
for( std::size_t j = i/4; j < Count/4; j++, i += 4 )
{
const __m128i QuadPixel = _mm_stream_load_si128((__m128i*)&Pixels[i]);
RedGreenSum64 = _mm_add_epi64( // Add it to the 64bit accumulators
RedGreenSum64,
_mm_sad_epu8( // compute  0+G+0+G+0+G+0+G  0+R+0+R+0+R+0+R 
_mm_shuffle_epi8( // Shuffle the bytes to  0G0G0G0G  0R0R0R0R 
QuadPixel,
_mm_set_epi8(
// Green
1,13,1, 5,
1, 9,1, 1,
// Red
1,12,1, 4,
1, 8,1, 0
)
),
// SAD against 0, which just returns the original unsigned value
_mm_setzero_si128()
)
);
BlueAlphaSum64 = _mm_add_epi64( // Add it to the 64bit accumulators
BlueAlphaSum64,
_mm_sad_epu8( // compute  0+A+0+A+0+A+0+A  0+B+0+B+0+B+0+B 
_mm_shuffle_epi8( // Shuffle the bytes to  0A0A0A0A  0B0B0B0B 
QuadPixel,
_mm_set_epi8(
// Alpha
1,15,1, 7,
1,11,1, 3,
// Blue
1,14,1, 6,
1,10,1, 2
)
),
// SAD against 0, which just returns the original unsigned value
_mm_setzero_si128()
)
);
}
After doing chunks of 4 at a time, it can handle the unaligned pixels(there will only ever be 3 or less leftover) by extracting the 64bit accumulators from the vectorregisters, and falling back to the usual serial method.
Though there are some slight optimizations that can be done here too. bextr
can extract continuous bits a little quicker without doing a shiftandamask to get the upper color channels. x86 has register aliasing for the lower two bytes of its general purpose registers though so a bextr
would probably be overhandling for the lower color channels in the lower bytes.
// Extract the 64bit accumulators from the vector registers of the previous loop
std::uint64_t RedSum64 = _mm_cvtsi128_si64(RedGreenSum64);
std::uint64_t GreenSum64 = _mm_extract_epi64(RedGreenSum64,1);
std::uint64_t BlueSum64 = _mm_cvtsi128_si64(BlueAlphaSum64);
std::uint64_t AlphaSum64 = _mm_extract_epi64(BlueAlphaSum64,1);
// New serial method
for( ; i < Count; ++i )
{
const std::uint32_t CurColor = Pixels[i];
AlphaSum64 += _bextr_u64( CurColor, 24, 8);
BlueSum64 += _bextr_u64( CurColor, 16, 8);
// I'm being oddly specific here to make it obvious for the
// compiler to do some ah/bh/ch/dh register trickery
// V
GreenSum64 += static_cast<std::uint8_t>( CurColor >> 8 );
RedSum64 += static_cast<std::uint8_t>( CurColor );
}
// Average
RedSum64 /= Count;
GreenSum64 /= Count;
BlueSum64 /= Count;
AlphaSum64 /= Count;
// Interleave
return
(static_cast<std::uint32_t>( (std::uint8_t)AlphaSum64 ) << 24 ) 
(static_cast<std::uint32_t>( (std::uint8_t) BlueSum64 ) << 16 ) 
(static_cast<std::uint32_t>( (std::uint8_t)GreenSum64 ) << 8 ) 
(static_cast<std::uint32_t>( (std::uint8_t) RedSum64 ) << 0 );
This implementation so far with a 3840x2160 image on an i77500U shows an approximate x2.6 increase in performance over the serial method. It now takes less than half the time to process an image now.
Serial: #10121AFF  7100551ns
Fast : #10121AFF  2701641ns
Speedup: 2.628236
With AVX2 this algorithm can be updated to process 8 pixels a time, then 4 pixels a time before resorting to the serial algorithm for unaligned data(there will only be 7 or less unaligned pixels, think greedy algorithms). With much larger 256bit vectors, all four 64bit accumulators can reside within a single AVX2 register.
Though, AVX2's massive 256bit vectorregisters is almost just an alias for two regular 128bit SSE registers from before with the additional benefit of being able to compactly handle two 128bit registers with 1 instruction.
This also means that crosslane arithmetic(shuffling elements across the full width of a 256bit register, rather than staying within the upper and lower 128bit halfs) can be tricky as crossing the 128bit boundary needs some special attention. A solution to this is to shuffle first within the upper and lower 128bit lanes, and then using a much larger crosslane shuffle to further unpack the channels into continuous values before computing a _mm256_sad_epu8
on each of the four 64bit lanes.
// Vector of four 64bit accumulators for Red,Green,Blue, and Alpha
__m256i RGBASum64 = _mm256_setzero_si256();
// 8 pixels at a time! (AVX/AVX2)
for( std::size_t j = i/8; j < Count/8; j++, i += 8 )
{
const __m256i OctaPixel = _mm256_loadu_si256((__m256i*)&Pixels[i]);
// Shuffle within 128bit lanes
//  ABGRABGRABGRABGR  ABGRABGRABGRABGR 
//  AAAABBBBGGGGRRRR  AAAABBBBGGGGRRRR 
// Setting up for 64bit lane sad_epu8
__m256i Deinterleave = _mm256_shuffle_epi8(
OctaPixel,
_mm256_broadcastsi128_si256(
_mm_set_epi8(
// Alpha
15,11, 7, 3,
// Blue
14,10, 6, 2,
// Green
13, 9, 5, 1,
// Red
12, 8, 4, 0
)
)
);
// Crosslane shuffle
//  AAAABBBBGGGGRRRR  AAAABBBBGGGGRRRR 
//  AAAAAAAA  BBBBBBBB  GGGGGGGG  RRRRRRRR 
Deinterleave = _mm256_permutevar8x32_epi32(
Deinterleave,
_mm256_set_epi32(
// Alpha
7, 3,
// Blue
6, 2,
// Green
5, 1,
// Red
4, 0
)
);
//  ASum64  BSum64  GSum64  RSum64 
RGBASum64 = _mm256_add_epi64(
RGBASum64,
_mm256_sad_epu8(
Deinterleave,
_mm256_setzero_si256()
)
);
}
// Pass the accumulators onto the next SSE loop from above
__m128i BlueAlphaSum64 = _mm256_extractf128_si256(RGBASum64,1);
__m128i RedGreenSum64 = _mm256_castsi256_si128(RGBASum64);
for( std::size_t j = i/4; j < Count/4; j++, i += 4 )
{
...
This implementation so far(AVX2,SSE,and Serial) with the same 3840x2160 image as before on an i77500U shows an approximate x4.1 increase in performance over the serial method. It now takes less than a forth of the time to calculate the color average over the serial version!
Serial: #10121AFF  7436508ns
Fast : #10121AFF  1802768ns
Speedup: 4.125050
RGB8? RG8? R8?
Not explored in this little writeup are other pixel formats such as the threechannel RGB
with no alpha or just a 2channel RG
image or even just a monochrome "R8" image of just one channel.
Other formats will work with the same principle as the RGBA
format one so long as you account for the proper shuffling needed.
Depending on where you are at in your pixel processing, consider the different cases of how you can take a 16byte chunk out of a stream of 3byte RGB
pixels
If your bytes were organized RGBRGBRGBRGB...
and a vectorregister with a width of 16bytes, then you'll always be taking 16/3 = 15.3333...
RGB
pixels at once. And every 3rd chunk (0.333.. * 3 = 1.0
) is when the period repeats. So only 3 shufflemasks are ever needed depending on where your index i
lands on the array. Some ASCII art might help visualize it
Note how different the bytes align when taking regular 16byte chunks out of a
stream of 3byte pixels.
Different shuffle patterns must be used to account for each case:
>RGBRGBRGBRGBRGBRG<
0:SIMD Reg.
RGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGB...
>BRGBRGBRGBRGBRGBR<
1: SIMD Reg.
RGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGB...
>GBRGBRGBRGBRGBRGB<
2: SIMD Reg.
RGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGB...
This is the same as iteration 0 >RGBRGBRGBRGBRGBRG<
3: SIMD Reg.
RGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGB...
You can also process much larger 48byte (lcd(16,3)
) aligned chunks to have more productive iterations at a higher granularity:
Now you don't have to worry about bytelevel alignment and can do all the shuffles at once
>RGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGB<
0:SIMD Reg.SIMD Reg.SIMD Reg.
RGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGBRGB...
Once you got your sums, then it's just a division and interleave to turn these statistical averages into a new color value.
For RG8, the same principle applies but much more trivial since 2byte pixels naturally align themselves with poweroftwo register widths.
For R8, the summing step reduces to just be a sumofbytes which is a topic precisely covered by Wojciech MuΕa. After getting the sum, divide by the number of pixels to get the statistical average.
Wunkolo / qAverageColor
SIMD accelerated method to get the average color of an RGBA8 image
qAverageColor
Serial  SSE4.2  AVX2  AVX512  
Processor  Speedup  
i77500u    x2.8451  x4.4087  N/A 
i36100    x2.7258  x4.2358  N/A 
i58600k    x2.4015  x2.6498  N/A 
i97900x    x2.0651  x2.6140  x4.2704 
i71065G7    x3.9124  x4.6244  x5.4683 
^{Tested against a synthetic 10megapixel image, GCC version 8.2.1}
This is a little snippet writeup of code that will find the average color of an image of RGBA8 pixels (32bits per pixel, 8 bits per channel) by utilizing the psadbw
(_mm_sad_epu8
) instruction to accumulate the sum of each individual channel into a (very overflowsafe)64bit accumulator.
Inspired by the "SIMDized sum of all bytes in the array" writeup by Wojciech MuΕa.
The usual method to get the statistical average of each color channel in an image is pretty trivial:
 Load in a pixel
 Unpack the individual color channels
 Sum the channel values into a an accumulator
 When you've summed them all, divide these sums by theβ¦
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