There's one critical point of .sort() that I feel you should mention in the article: the .sort() method sorts an array in place, it does not return a sorted copy of the array...
.sort()
Basically, if you do the following:
const myThings = [5,2,4,3,6,1]; const sortedThings = myThings.sort();
..then both variables will contain the same thing:
myThings; // [1,2,3,4,5,6] sortedThings; // [1,2,3,4,5,6] myThings === sortedThings; // true
With this in mind, your example could be simplified to the following:
const arr = [1, 2, 3, 4, 5, 6]; const alpha = ['e', 'a', 'c', 'u', 'y']; // sort in descending order arr.sort((a, b) => a > b ? -1 : 1); console.log(arr); // output: [6, 5, 4, 3, 2, 1] // sort in ascending order alpha.sort((a, b) => a > b ? 1 : -1); console.log(alpha); // output: ['a', 'c', 'e', 'u', 'y']
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There's one critical point of
.sort()that I feel you should mention in the article: the.sort()method sorts an array in place, it does not return a sorted copy of the array...Basically, if you do the following:
..then both variables will contain the same thing:
With this in mind, your example could be simplified to the following: