Day 3 I4G 10 days of code challenge

Early in the morning after I wake up, I decided to start with todays code challenge before anything else;

The problem was given an integer you return true when it's a palindrome, else return false.
Palindrome are numbers,phrase or strings that when reversed the result is the same number;
e.g 1221 is a palindrome and will return true. 1234 is not a palindrome and will return false.

The solution i think is to covert the integer to a string;
Reverse the string;
Convert the reversed string to an integer;
Compare the original integer and the reversed Integer,
If they are the same return true
Else return false

Time complexity
O(n)
Space complexity
O(n)
Leetcode problem
Link to Implementation