nice. for higher order function lovers , we can do the same thing by
const nums = [1, 2, 2, 3, 1, 2, 4, 5, 5, 6, 4, 2, 6]; nums.filter((v,i) => nums.indexOf(v) == i );
numsObject = [{id: 1, name: 'one', {id: 2, name: 'two'}] ?
Like @lukeshiru said, this works but is much slower. O(n^2) vs O(n). It's fine for small arrays, but would be slow as the array gets bigger.
O(n^2)
O(n)
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nice.
for higher order function lovers , we can do the same thing by
numsObject = [{id: 1, name: 'one', {id: 2, name: 'two'}] ?
Like @lukeshiru said, this works but is much slower.
O(n^2)vsO(n). It's fine for small arrays, but would be slow as the array gets bigger.