How Constructors Work in Inheritance
When a subclass object is created, constructors of both parent and child are involved:
- Parent class constructor executes first.
- super() is implicitly added in every constructor of sub class.
- Child class constructor executes next.
This ensures that parent class fields are initialized before child class fields.
Java compiler does not implicitly call parameterized parent class constructor unless we insert super(args) in subclass constructors.
If parent has only parameterized constructors, child must explicitly call one using super(args).
If you explicitly write super(args), then the compiler will NOT add super().
Case 1


Case 7:Explicitly super(args) written


Case 8 :If parent has only parameterized constructors, child must explicitly call one using super(args).








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