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Discussion on: Understanding JavaScript async/await in 7 seconds

 
frenkix profile image
Goran Jakovljevic • Edited

Ah sorry, I didn't read it correctly.

Yeah, promise.all wont resolve with a single reject, so what I would do is return an error as a normal result instead of rejecting, and then filter out errors after promises finish. Until they make something like .every available for .all as well.

And while it might be strange to have errors passing into resolve, as long as your code is expecting them, I see nothing wrong in it.

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wassimchegham profile image
Wassim Chegham • Edited

Hey, so for your particular use case, I would try this:

const profilePromise = getProfile(this.id);
const commentsPromise = getComments(this.id)
const friendsPromise = getFriends(this.id);

this.profile = await profilePromise;
this.comments = await commentsPromise;
this.friends = await friendsPromise;

Here is a working proof of concept:

const func = (t, f) => new Promise( (res, rej) => { setTimeout( () => res(f()), t )  } )
const a = func(2000, () => console.log('func 1'));
const b = func(0, () => console.log('func 2'));
const c = func(0, () => console.log('func 3'));
const [f1, f2, f3] = [await a, await b, await c];

console.log(f1, f2, f3);

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madslundt profile image
Mads

To run them parallel there is this approach:

const result = await Promise.all([
  getProfile(this.id), 
  getComments(this.id),
  getFriends(this.id),
]);

However, this waits for all to finish and does not replace the first I descried, as I see it?

As I see it the only way to avoid this with async/await is to wrap the promises into their own function and run it in Promise.all. Like this (haven't tested this yet):

await Promise.all([
  async () => { this.profile = await getProfile(id); },
  async () => { this.comments = await getComments(id); },
  async () => { this.friends = await getFriends(id); },
]);
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prasannasridharan profile image
Prasanna-Sridharan

Hi,
As I see it, in both cases the inner methods run async and the end promise is awaited so it would not be blocking the current thread anyway.
When I get time, will execute 2nd e.g. but highly doubt if it has any difference in behavior compared to 1st.