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In Python ord()
function accepts a single unit of character and returns the equivalent Unicode of the passed argument. In other words, the ord()
function can take a string or character of length one and returns an integer representing the Unicode of that string or character.
ord() Function in Python
The ord()
function is nothing but the inverse of the Python chr()
function. In the chr()
function, we will convert the Unicode integer to the character, and in the ord()
, it will be the exact opposite in the ord ()
.
Syntax – ord(ch)
Parameters : ** ** Accepts Unicode character or string of length 1.
Return Value : Returns an integer representing the Unicode character
*Example ord() vs chr() *
print(chr(97))
print(ord('a'))
Output
a
97
As you can see, the chr(97)
returns character ‘a’ , and the inverse*ord('a')
returns the integer **97*
ord() Function Examples
Let’s take a look at different types of example.
print('Unicode of lower case alphabet a is ', ord('a')) # lower case alphabet
print('Unicode of bumber 5 is ', ord('5')) # Number
print('Unicode of symobol $ is ', ord('$')) # dollar
print('Unicode of upper case alphabet A is ', ord('A')) # Upper case alphabet
print('Unicode of zero is ', ord('0')) # Number Zero
Output
Unicode of lower case alphabet a is 97
Unicode of bumber 5 is 53
Unicode of symobol $ is 36
Unicode of upper case alphabet A is 65
Unicode of zero is 48
TypeError: ord() expected a character, but string of length 2 found.
If the argument passed to the ord()
function is more than 1 character, then Python will raise a TypeError: ord()
expected a character, but string of length 2 found.
print(ord('AB'))
Output
Traceback (most recent call last):
File "c:\Projects\Tryouts\main.py", line 9, in <module>
print(ord('AB'))
TypeError: ord() expected a character, but string of length 2 found
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