Discussion on: Daily Challenge #117 - MinMinMax

[kesprit]

My solution in Swift, I check if the array is not empty and bigger than two elements :

func minMinMax(array: [Int]) -> [Int] {
    guard !array.isEmpty, array.count > 2,
        let min = array.min(),
        let max = array.max(),
        let minimumAbsent = ((min...max).first{!array.contains($0)})
        else {
            return []
    }
    return [min, minimumAbsent, max]
}