there are three methods to reverse a linked list using stack, Iterative and Recursion method
While stack and recursion method is easier understand iterative method is easier to implement
Approach Explanation o( ̄▽ ̄)o
- Start with two pointers: 1.1. curr → the current node you’re processing. 1.2. prev → the node that will become the new "next" for curr. 1.3. Initially None.
- For each node: 2.1. Save the next node (nextNode = curr.next). 2.2. Reverse the link (curr.next = prev). 2.3. Move prev forward (prev = curr). 2.4. Move curr forward (curr = nextNode).
- When curr becomes None, prev points to the new head of the reversed list.
Method Used: (〜 ̄▽ ̄)〜
- Pointer manipulation
- Iterative traversal
- In-place reversal
- Efficient runtime

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