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Discussion on: Type Safety in C++

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sandordargo profile image
Sandor Dargo •

The compiler might or might not warn you if you demote or narrow variables.

Try this:

#include <iostream>

int main() {
  unsigned int i = -5;
  short x = (short)0x12345678L;
  std::cout << i << std::endl;
  std::cout << x << std::endl;
}
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There is no compiler warning at all.

On the other hand, if you use a {}-initialization, you'll receive a compiler warning about a narrowing conversion.

#include <iostream>

int main() {
  unsigned int i {-5};
  std::cout << i << std::endl;
}
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blender profile image
Saloni Goyal •

Yes 🤩, the first method didn't give any warning. The second one gave a compiler error on Xcode.
error