Edit: I just tried this on macOS and it errors out with sed: 1: ".git/COMMIT_EDITMSG": invalid command code .. With some searching, I learnt that BSD sed (the one that macOS uses) requires an extension with -i. However, even that gives me sed: 1: "/^# Please/,+2 d": expected context address. Apparently the +2 thing is GNU sed specific. The first statement (with -i.bak) didn't error, but didn't remove the lines either. I'm guessing it's because of inconsistencies in implementations of sed.
Does the other sed command work for you (sed -i.bak '/\(# Please.*\|# with.*\|^#$\)/ d' $1)?
You can also try this one: sed -i.bak '/^# Please/,/^#$/ d' $1
To keep things tidy you could make it sed -i.bak '/^# Please/,/^#$/ d' $1 && rm $1.bak
Great idea. I'll update the article to use this.
Edit: I just tried this on macOS and it errors out with
sed: 1: ".git/COMMIT_EDITMSG": invalid command code .. With some searching, I learnt that BSDsed(the one that macOS uses) requires an extension with-i. However, even that gives mesed: 1: "/^# Please/,+2 d": expected context address. Apparently the+2thing is GNU sed specific. The first statement (with-i.bak) didn't error, but didn't remove the lines either. I'm guessing it's because of inconsistencies in implementations ofsed.Does the other
sedcommand work for you (sed -i.bak '/\(# Please.*\|# with.*\|^#$\)/ d' $1)?You can also try this one:
sed -i.bak '/^# Please/,/^#$/ d' $1To keep things tidy you could make it
sed -i.bak '/^# Please/,/^#$/ d' $1 && rm $1.bakPerfect.