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Siddhesh Agarwal
Siddhesh Agarwal

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id() in python

In this post, I will try to improve your idea about memory in python using the in-built id() function. For those of you who don't know what id() is:

The id() function returns a unique ID of the object. All objects in python have a unique ID and no 2 different values correspond to the same ID.

So let us begin with a small example:

a = b = 500
print(id(a) == id(b))
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Fun fact: In python, id(a) == id(b) is analogous to a is b.

The above code prints True because python creates the variable b with the value 500 and then creates a variable a pointing to the value of b. This implies that a and b are pointing towards the same memory location and hence the same ID.


Now let us raise the bar:

a = 500
b = 500
print(id(a) == id(b))
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The above code prints False because:

  • Python creates a variable a pointing to the value 500 in the memory.
  • Then it creates another variable b pointing to another value 500 (yeah, both 500 are different).

Hence, both have different IDs because both point towards different memory locations.


I hope this isn't confusing because there is more to come. Guess the output for this:

a = 50
b = 50
print(id(a) == id(b))
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Some of you may think "This is the previous question with different values. I know the answer is False" but not so fast.

Not so fast

For small integers (The CPython range is -5 to 256, both inclusive), then integer objects (<class 'int'>) are shared. This is done entirely to save space. The memory imprint of the console would be significantly larger if these objects weren’t sharing their memory.

So the correct answer is True


Okay, okay. Just one more to go. The last one:

a = 500
id1 = id(a)
a = 500
id2 = id(a)
print(id1 == id2)
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Well, even though I am re-declaring the same variable with the same value, the answer is most likely to be False. I'll explain to you why. When you re-declare a variable in python, the interpreter works in the same way as a declaration. i.e. It entirely deletes the before existing value and creates a variable with the new value. So when we give a = 500, the second time the interpreter deletes the previously existing value of a and create a new memory location for 500 where a would point towards. Both these IDs are most likely to be different.

SO, the answer is False.

NOTE: If the above example had a number belonging to the inclusive range -5 to 256, the answer would have been True. this is because number belonging to the inclusive range have a fixed memory location.

Top comments (3)

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shreevarshan profile image
Shree-Varshan

U did a good job❤️

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rajshiikhar1691999 profile image
Rajshiikhar1691999

a = 500
id1 = id(a)
a = 150
id2 = id(a)
print(id1 == id2)
Now it is false na.

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siddhesh_agarwal profile image
Siddhesh Agarwal

The example is talking about re-initialization with same value like this:

a = 150
id1 = id(a)
a = 150
id2 = id(a)
print(id1 == id2)
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The above code gives True