So while Mohammad was commiserating the Indians losing to the Black Caps last night, as a Kiwi living in Australia I was a very happy boy. Well done to Kane Williamson and the lads.

## TASK #1 › Long Year

### Task

Write a script to find all the years between 1900 and 2100 which is a Long Year.

### My solution

When we switched to the Gregorian calendar in 1752, they definitely didn't have computers in their mind. Date math really sucks. If we thought Y2K was serious, I suspect (the non-existent) 29/2/2100 is going to be even worse. We've got to deal with the 2038 date problem first. But I digress.

The terms 'long year' and '53 week years' aren't used at all in New Zealand and Australia, so I had to look up the meaning. According to this article "if the year starts on a Thursday or is a leap year that starts on a Wednesday, that particular year will have 53 numbered weeks. These week numbers are commonly used in some European and Asian countries; but not so much in the United States."

This seems rather simple exercise after that. We start with the fact that 1/1/1900 was a Monday. I set `$year`

to 1900 and `$day_of_week`

to 1 (where 0 = Sunday, 6 = Saturday). If day of week is 4 (Thursday) or 3 (Wednesday) in a leap year, I add it to the `@long_years`

array.

The next fact is the first day of the next year is either one day (or two days for leap years) later than the current year. For example, 1/1/1900 was a Monday, so 1/1/1901 was a Tuesday. Remember 1900 was NOT a leap year. I change `$year`

and `$day_of_week`

as required, and keep running the loop until 2100.

Comparing the output to the example gives the same result, so hopefully it's all good.

### Examples

```
$ ./ch-1.pl
1903, 1908, 1914, 1920, 1925, 1931, 1936, 1942, 1948, 1953, 1959, 1964, 1970, 1976, 1981, 1987, 1992, 1998, 2004, 2009, 2015, 2020, 2026, 2032, 2037, 2043, 2048, 2054, 2060, 2065, 2071, 2076, 2082, 2088, 2093, 2099
```

## TASK #2 › Lychrel Number

### Task

You are given a number, 10 ≤ $n ≤ 1000.

Write a script to find out if the given number is Lychrel number. To keep the task simple, we impose the following rules:

- Stop if the number of iterations reached 500.
- Stop if you end up with number >= 10,000,000.

### My solution

If I thought date math was hard, number theory blows my mind. The Wikipedia page contains the equation below, which I don't even know where to begin!

So it's the brute force method for me. One great thing about Perl is that distinction between a number and a string that contains a number is almost non-existent. I know in the internals it's different, but from a coding point of view the transition between the two is seamless.

I check if the input is palindromic by comparing using the reverse function (which reverses the string in a scalar context). If it isn't I add the two numbers together and repeat the process until it is a match or we have reached the rules above.

### Example

```
$ ./ch-2.pl 56
0
$ ./ch-2.pl 57
0
$ ./ch-2.pl 59
0
$ ./ch-2.pl 788
1
```

## Top comments (0)