DEV Community

Cover image for Gear Ratio: Trading Speed for Torque on Purpose
NovaSolver
NovaSolver

Posted on • Originally published at novasolver.jp

Gear Ratio: Trading Speed for Torque on Purpose

A bicycle in its lowest gear barely moves for each turn of the cranks, yet a hill that felt impossible suddenly becomes climbable. Nothing about the rider's strength changed — only the gear ratio did. That trade, sacrificing speed to gain force, is the single most useful idea in mechanical power transmission, and it shows up in everything from wristwatches to wind turbines.

This article explains where gear ratio comes from, how it reshapes speed and torque, and how to chain ratios across a multi-stage train, with a worked example you can check on paper.

Why this calculation matters

Almost no motor produces power at the speed and torque a machine actually needs. Electric motors like to spin fast at modest torque; wheels, conveyors, and robot joints often need the opposite. The gear ratio is the conversion factor that bridges that gap.

Get the ratio right and the motor runs in its efficient band while the output delivers the force the job demands. Get it wrong and you either stall a motor that cannot supply enough torque, or run an actuator far too slowly to be useful. The ratio also fixes rotational direction and, in a gear train, decides how many stages you need and how large the final gear must be. It is a design decision made early, because almost every other sizing choice depends on it.

The core method

For a pair of meshing gears, the gear ratio is simply the tooth count of the driven gear divided by the tooth count of the driver:

i = N2 / N1
Enter fullscreen mode Exit fullscreen mode

N1 is the teeth on the driving gear (often the pinion), N2 is the teeth on the driven gear. When i is greater than 1 the pair is a reduction: the output turns slower than the input. Because meshing teeth must move at the same pitch-line speed, the speeds are inversely related to tooth count:

n2 = n1 / i
Enter fullscreen mode Exit fullscreen mode

Power is conserved apart from friction losses, and power is the product of torque and angular speed. So if speed drops by the factor i, torque must rise by very nearly the same factor:

T2 = T1 * i * eta
Enter fullscreen mode Exit fullscreen mode

Here eta is the mesh efficiency, a number a little below 1 that accounts for tooth friction and churning losses. A well-made spur mesh often runs around 0.97 to 0.99 per stage.

For a multi-stage train, the overall ratio is just the product of the individual stage ratios:

i_total = i1 * i2 * i3 * ...
Enter fullscreen mode Exit fullscreen mode

This is why a compact gearbox can achieve a ratio of 100:1 or more — three modest stages of about 4.6:1 each multiply together rather than add.

A worked example

Consider a single spur-gear pair. The pinion is the driver with N1 = 20 teeth; the gear is driven with N2 = 60 teeth.

Step 1 — gear ratio.

i = N2 / N1 = 60 / 20 = 3
Enter fullscreen mode Exit fullscreen mode

That is a 3:1 reduction.

Step 2 — output speed. If the pinion turns at n1 = 1500 rpm:

n2 = n1 / i = 1500 / 3 = 500 rpm
Enter fullscreen mode Exit fullscreen mode

The gear turns at one third of the pinion's speed.

Step 3 — output torque. Take an input torque of 10 N.m and a mesh efficiency of 0.97:

T2 = T1 * i * eta = 10 * 3 * 0.97 = 29.1 N.m
Enter fullscreen mode Exit fullscreen mode

The output torque is almost three times the input. Without losses it would be exactly 30 N.m; the 3 % efficiency penalty trims it to 29.1 N.m. The pattern is clean: divide the speed by the ratio, multiply the torque by it, and let efficiency take a small cut. For a multi-stage train, you would simply multiply the stage ratios together first and apply the same logic to the total.

Common mistakes

Inverting the ratio. Driven over driver gives a reduction; driver over driven gives a step-up. Picking the wrong order turns a torque multiplier into a speed multiplier. Always anchor the definition to which gear receives the power.

Assuming torque is multiplied for free. Torque rises with the ratio only because power is conserved. Real meshes lose a few percent per stage, and in a deep train those losses compound — five stages at 0.97 each leave only about 0.86 of the input power.

Forgetting direction. An external spur pair reverses rotation at every mesh. An idler gear changes direction without changing the overall ratio. Count your meshes if direction matters.

Confusing gear ratio with mechanical advantage at the load. The gear ratio sets the shaft torque. What a wheel or lever finally delivers also depends on radius and linkage geometry downstream.

Ignoring tooth-count limits. Very small pinions can suffer undercutting and weak teeth. A ratio that looks fine on paper may force a pinion too small to be practical, pushing you toward a two-stage solution.

Try the interactive NovaSolver calculator

Working one pair by hand is straightforward, but real drivetrains involve compound trains and planetary sets where the bookkeeping gets fiddly. The Gear Ratio Calculator & Visualizer on NovaSolver lets you choose a simple pair, a compound train, or a planetary set, enter tooth counts, input speed, torque, efficiency, and module, and instantly see the gear ratio, output speed, output torque, transmitted power, and output pitch diameter — alongside a meshing animation that shows rotation direction.

Related calculators

You can explore the rest of the drivetrain toolkit in the mechanical engineering tools hub.

Closing note

Gear ratio is a small piece of arithmetic with a large reach. Tooth counts set the ratio; the ratio divides speed and multiplies torque; efficiency takes a modest cut; and stage ratios multiply across a train. Once those four facts are second nature, sizing a gearbox becomes a matter of deciding what speed and torque the load needs and working backward. Pick the ratio first, and the rest of the drivetrain tends to fall into place.

Top comments (0)