Inspired by Alessio Saltarin's Primality Test in Scala, I thought that it would be interesting to implement the same primality test in rust and then use this test as a means to build an Iterator that lazily generates prime numbers.

The primality test is based on the fact that all primes greater than 3 are of the form 6k ± 1, where k is any integer greater than 0. The rust version of this algorithm is:

```
pub fn is_prime(n: u64) -> bool {
if n < 4 {
n > 1
} else if n % 2 == 0 || n % 3 == 0 {
false
} else {
let max_p = (n as f64).sqrt().ceil() as u64;
match (5..=max_p).step_by(6).find(|p| n % p == 0 || n % (p+2) == 0) {
Some(_) => false,
None => true
}
}
}
```

`is_prime`

first tests for `n<4`

and returns `n>1`

. `n=2`

or `n=3`

will return `true`

all other `n<4`

return `false`

. The next test checks if n is an even multiple of 2 or 3. If it is, return `false`

as n is not prime.

The final test checks to see if n is evenly divisible by any `6k ± 1`

up to the square root of n. This is done by starting at 5 and checking if n is an even multiple of 5 or 5+2, 6-1 or 6+1 respectively. If it is an even multiple we will return `false`

, if not we add 6 and test again. If no even multiple is found, n is prime and return `true`

.

Many will point out that using sqrt() and ceil() are expensive, but I only use it once up front to get the upper bound for the comparison. This removes the need to square the `6k ± 1`

in the test loop to determine when to break. It also allowed me to use the range `(5..=max_p).step_by(6).find`

with the predicate `|p| n % p == 0 || n % (p+2) == 0`

to identify non-primes. I add that to a match statement to return `false`

if a non-prime is identified and `true`

if n is prime.

Now that we have a primality test we can construct the lazy prime Iterator in rust. The code for the Iterator is:

```
pub struct Prime {
curr: u64,
next: u64,
}
impl Prime {
pub fn new() -> Prime {
Prime {
curr: 2,
next: 3,
}
}
}
impl Iterator for Prime {
type Item = u64;
fn next(&mut self) -> Option<Self::Item> {
let prime = self.curr;
self.curr = self.next;
loop {
self.next += match self.next%6 {
1 => 4,
_ => 2,
};
if is_prime(self.next) {
break;
}
}
Some(prime)
}
}
```

A new Prime starts off with curr=2 and next=3. This allowed me to ignore the special case of two primes being only one digit apart. The next function saves the prime in `curr`

which it will return. It then moves `next`

into `curr`

and calculates a new `next`

. It makes use of the fact that all primes greater than 3 are of the form 6k ± 1. So if the latest test prime is 6k-1 we add 2 to get the next possible prime. If the latest test prime is 6K+1 we add 4 to get the next possible prime. We accomplish this with p modulo 6, where p is the latest test prime. If p modulo 6 is 1 then we have a 6k+1 number and need to add 4 to get to the next test prime of 6k-1. If p modulo 6 is 5 or 3, then we add 2 to get to the next 6k+1 number. `_ => 2`

is the catch all that let's us catch the initial state of n=3 and any state where n=6k-1.

This iterator operates with constant memory and only generates one prime at a time, but it performs a modulo and match operation inside the loop. After some consideration, both the modulo and match can be removed from inside the loop. If we initialize the `struct Prime`

with the first two primes and the first `6k ± 1`

we only need to add 6 to get the next trial prime. The final Iterator is:

```
pub struct Prime {
curr: u64,
next: u64,
trial1: u64,
trial2: u64
}
impl Prime {
pub fn new() -> Prime {
Prime {
curr: 2,
next: 3,
trial1: 5,
trial2: 7
}
}
}
impl Iterator for Prime {
type Item = u64;
fn next(&mut self) -> Option<Self::Item> {
let prime = self.curr;
self.curr = self.next;
loop {
self.next = self.trial1;
self.trial1 = self.trial2;
self.trial2 = self.next+6;
if is_prime(self.next) {
break;
}
}
Some(prime)
}
}
```

Full code can be found on GitHub

## Top comments (1)

Good work!