Question:
Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn't one, return 0 instead.
Example:
Input: s = 7, nums = [2,3,1,2,4,3]
Output: 2
Explanation: the subarray [4,3] has the minimal length under the problem constraint.
Solution:
Time complexity: O(n)
Space complexity: O(1)
var minSubArrayLen = function(s, nums) {
let windowSum = 0
let output = Infinity;
let windowStart = 0;
for (let windowEnd = 0; windowEnd < nums.length; windowEnd++) {
windowSum += nums[windowEnd];
// shrink the window until the windowSum is smaller than s
while (windowSum >= s) {
output = Math.min(output, windowEnd - windowStart + 1);
// subtract the element at the windowStart index
windowSum -= nums[windowStart];
// change windowStart to the next element
windowStart++;
}
}
return output == Infinity ? 0 : output;
};
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