What about:
cont newArr = [...oldArr, newItem]
🤔
I tried this out in the babel repl, the spread uses concat after es6 code gets transpiled so I can assume its probably the same :O
babeljs.io/repl/#?babili=false&bro...
Doesn't that still create a copy of the first array - which makes it the same as the concat?
concat
I don't know actually. If so, that's really insightful thank you, I'll investigate!!
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What about:
cont newArr = [...oldArr, newItem]
🤔
I tried this out in the babel repl, the spread uses concat after es6 code gets transpiled so I can assume its probably the same :O
babeljs.io/repl/#?babili=false&bro...
Doesn't that still create a copy of the first array - which makes it the same as the
concat?I don't know actually. If so, that's really insightful thank you, I'll investigate!!