Hi there, I hope you’re doing good.
I’m doing well as well and we are still pushing through the challenge and today was a review of some of the concepts learnt so far such as strings, input/output, conditionals and loops.
Given a string S of length N that is indexed from 0 to N-1, print its even-indexed and odd-indexed characters as 2 space-separated strings on a single line.
For the input format: the first line contains an integer, T (the number of test cases) and each line i of the T test cases contains a string S.
From the given challenge we can break it down to the steps we need to carry out to complete it:
• Accept an input for the number of test cases one will need.
• Loop through the number of test cases and accept input for the strings
• Loop through each string and determine which characters are even-indexed and which are odd-indexed and store them in a variable.
• Print the final output as expected.
#integer input for the number of test cases N = int(input()) #variables to hold the even and odd indexed characters; I used lists. index_even =  index_odd =  #looping through each test case for i in range(0,N): #input for the string string = input() #empty the lists if they hold any strings index_even.clear() index_odd.clear() #loop through the string; item(index value) and char(character value) #enumerate() method eases looping through the string for item , char in enumerate(string): #conditional to check if the index is odd or even. #if even, the character is added to the index_even list respectively if item % 2 == 0: index_even.append(char) else: index_odd.append(char) #transform the characters in the list to form a single word. print(''.join(index_even), ''.join(index_odd)) ''' Sample Input: 2 Hacker Rank Sample Output: Hce akr Rn ak '''
Every time one is learning something new, things tend to look foreign but with the help of Google you can be able to pick up a thing two and get yourself unstuck (There is nothing wrong with going to google for help).