Airdrops have become a primary utility for new blockchain projects to distribute tokens and drive early adoption. However, manually tracking eligibility across dozens of protocols is inefficient and error-prone. By leveraging AI, you can build an automated monitor that not only tracks on-chain activity but also interprets complex eligibility criteria from unstructured documentation. This guide walks you through building a robust Airdrop Monitor using Python, web scraping, and Large Language Models (LLMs).
The Architecture
The system requires three core components: a data collector, an AI interpreter, and a notification engine. The data collector scrapes official project websites and Twitter/X feeds for updates. The AI interpreter uses an LLM to parse natural language announcements (e.g., "Users with 50+ transactions on Testnet A are eligible") into structured JSON data. Finally, the notification engine pushes alerts to your Discord or Telegram.
Step 1: Data Ingestion
Start by fetching raw text from project sources. Use BeautifulSoup for HTML parsing and requests for API calls.
import requests
from bs4 import BeautifulSoup
def fetch_project_page(url):
response = requests.get(url, headers={'User-Agent': 'Mozilla/5.0'})
soup = BeautifulSoup(response.text, 'html.parser')
# Extract relevant sections, e.g., 'faq' or 'announcements'
return soup.find('section', class_='announcements').get_text()
Step 2: AI-Powered Interpretation
This is where AI shines. Instead of writing brittle regex patterns for every new project, send the scraped text to an AI API. Prompt the model to extract specific fields: eligibility_criteria, claim_date, and wallet_requirements.
python
import openai
def analyze_airdrop(text):
prompt = f"""
Analyze the following text for airdrop details.
Return only valid JSON with keys:
'eligibility_criteria' (string),
'claim_date' (ISO format or null),
'is_active' (boolean).
Text: {text}
"""
completion = openai.chat.completions.create(
model="gpt-4o-mini",
messages=[{"role": "user", "content": prompt}],
temperature=0.1
)
return completion.choices[
Top comments (0)