chessBoardColorCalculator

my solution to this code fights problem
https://app.codesignal.com/arcade/intro/level-6/t97bpjfrMDZH8GJhi/description

generates an odd and even offset board and checks their reference values

Given two cells on the standard chess board, determine whether they have the same color or not.

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def chessBoardCellColor(cell1, cell2):
[fooa, foob] = cell1
[bara, barb] = cell2

fooa = ord(fooa) % 2 
foob = int(foob) % 2

bara = ord(bara) % 2 
barb = int(barb) % 2

board = [[(i+1)%2 for i in range(0,9)], [i%2 for i in range(0,9)]]

return True if board[fooa][foob] == board[bara][barb] else False

`

Comments

[Domenico Barra]

Given that there are mathematical ways to compute their equality, you could probably skip the part where you generate the board.
A solution could be to just look at the cell indexes and how they relate to each other:

def color_equal(c1, c2):
    return ((c1[0] + c1[1]) % 2) == ((c2[0] + c2[1]) % 2)

>>> color_equal((1,1),(3,3))
True
>>> color_equal((1,1),(3,4))
False