Problem
Sort 0s, 1s and 2s
You are given an array arr[] containing only 0s, 1s, and 2s.
Your task is to sort the array in ascending order without using any built-in sort function.
Input: [0, 1, 2, 0, 1, 2] → Output: [0, 0, 1, 1, 2, 2]
Approach
This problem can be efficiently solved using the Dutch National Flag algorithm.
We divide the array into three regions:
- 0s on the left
- 1s in the middle
2s on the right
Steps:Use three pointers: low, mid, and high
-
Traverse the array once:
- If element is 0 → swap with low, move both pointers forward
- If element is 1 → move mid forward
- If element is 2 → swap with high, move high backward
This ensures sorting in a single pass without extra space.
Complexity:
Time Complexity: O(n)
Space Complexity: O(1)
def sort012(arr):
low = 0
mid = 0
high = len(arr) - 1
while mid <= high:
if arr[mid] == 0:
arr[low], arr[mid] = arr[mid], arr[low]
low += 1
mid += 1
elif arr[mid] == 1:
mid += 1
else:
arr[mid], arr[high] = arr[high], arr[mid]
high -= 1
return arr
arr = [0, 1, 2, 0, 1, 2]
print(sort012(arr))
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