πΉ Problem: 2966. Divide Array Into Arrays With Max Difference
Difficulty: #Medium
Tags: #Sorting, #Greedy
π Problem Summary
Given an array of integers
nums
, divide it into arrays of size 3 such that the maximum difference between the the elements in each array is at mostk
. Return an array of these arrays, or an empty array if it's not possible to divide the array as required.
π§ My Thought Process
- Brute Force Idea: The problem statement was a little confusing at first, but I realized it was about grouping numbers into sets of 3 with a maximum difference constraint.
- Optimized Strategy: Use sorting + greedy:
Sort the array to group similar numbers together.
Since groups of 3 are needed, scan in chunks of 3.
For each triplet: if
max - min <= k
, it's valid.If any triplet violates the rule, return an empty list immediately.
- Algorithm Used: [[sorting]] [[greedy]]
βοΈ Code Implementation (Python)
class Solution:
def divideArray(self, nums: List[int], k: int) -> List[List[int]]:
nums.sort()
res = []
for i in range(0,len(nums),3):
if nums[i+2] -nums[i] <= k:
res.append(nums[i:i+3])
else:
return []
return res
β±οΈ Time & Space Complexity
- Time: O(n log n) for sorting, O(n) for the loop, so overall O(n log n).
- Space: O(n) for the result list, but O(1) additional space if we ignore the output.
π§© Key Takeaways
- β What concept or trick did I learn? Sorting helps in grouping similar numbers, making it easier to check the max difference.
- π‘ What made this problem tricky? The initial confusion about the grouping and the maximum difference constraint.
- π How will I recognize a similar problem in the future? Look for problems that require grouping or partitioning with constraints, especially those involving differences or ranges.
π Reflection (Self-Check)
- [β ] Could I solve this without help?
- [β ] Did I write code from scratch?
- [β ] Did I understand why it works?
- [β ] Will I be able to recall this in a week?
π Progress Tracker
Metric | Value |
---|---|
Day | 23 |
Total Problems Solved | 344 |
Confidence Today | π |
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