Hey coders welcome to our new series of solving programming questions. So we are back with Leet Code solution in C++ and Python, so let's start.

**Problem Statement**

Given an integer number n, return the difference between the product of its digits and the sum of its digits.

**Example 1:**

`Input: n = 234`

Output: 15

Explanation:

Product of digits = 2 * 3 * 4 = 24

Sum of digits = 2 + 3 + 4 = 9

Result = 24 - 9 = 15

**Example 2:**

`Input: n = 4421`

Output: 21

Explanation:

Product of digits = 4 * 4 * 2 * 1 = 32

Sum of digits = 4 + 4 + 2 + 1 = 11

Result = 32 - 11 = 21

**C++ Solution**

```
class Solution {
public:
int subtractProductAndSum(int n) {
int sum = 0;
int product = 1;
while(n != 0){
int digit = n % 10;
sum += digit;
product = product * digit;
n = n / 10;
}
int subtract = product - sum;
return subtract;
}
};
```

**Python3 Solution**

```
def subtractProductAndSum(n):
sums = 0
product = 1
while(n != 0):
digit = n % 10
sums += digit
product = product * digit
n = n // 10
return (product - sums)
print(subtractProductAndSum(234))
```

So this was the simplest solution for this problem you can also try different approaches to solve this problem in a efficient way.

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