This post originally appeared as a guest article on PyBites.
PyBites community member
fusionmuck asked an interesting question in the Slack channel recently:
I am trying to get my head around the order of precedence. The test code is listed without brackets. In the second portion, I add brackets to test my understanding of precedence and I get a return value of True. I am missing something here...
Followed by this code sample:
>>> lst = [2, 3, 4] >>> lst * -3 < -10 == 0 False >>> (((lst) * (-3)) < (-10)) == 0 True
I love this question because there are a few different concepts colliding, but fusionmuck still has a clear question - "Why does Python do this when I expect it to do that?"
When I saw the question, I thought I understood at least part of what was going on. I needed to run some checks to be sure though, and this is fun stuff to play with. So let's do it together!
- Read or Experiment?
- Avengers... Disassemble!
- Bonus Round: Outside Python
- Takeaways and Related Reading
I mentioned that there were a few concepts colliding in the original question. It can be helpful to break down the code that we're trying to understand, and strip out as much noise as possible. So let's remove some elements like:
- Pulling items from a list
- Using 0 as a boolean (True/False) value
- Negative numbers
And come up with a pair of simpler comparisons that still demonstrate the behavior from the original question:
>>> 3 < 1 == False False >>> (3 < 1) == False True
We still might not be able to explain what's going on yet, but we have a much more focused question.
The original question was about operator precedence in Python. One way to answer that question is to check the official Python documentation. The sections on operator precedence and comparison chaining are definitely helpful:
Note that comparisons, membership tests, and identity tests, all have the same precedence and have a left-to-right chaining feature as described in the Comparisons section.
Comparisons can be chained arbitrarily, e.g., x < y <= z is equivalent to x < y and y <= z, except that y is evaluated only once (but in both cases z is not evaluated at all when x < y is found to be false).
Formally, if a, b, c, …, y, z are expressions and op1, op2, …, opN are comparison operators, then a op1 b op2 c ... y opN z is equivalent to a op1 b and b op2 c and ... y opN z, except that each expression is evaluated at most once.)
Applying that to our question, that means for a comparison like this:
3 < 1 == False
Python treats it like this:
3 < 1 and 1 == False
That makes things a lot clearer! Adding parentheses helps turn a chained comparison into separate, explicitly ordered operations.
But... what if we want to see that difference in action? What happens under the hood when we add those parentheses? We can't break down the code any more while preserving the behavior we're trying to observe, so
print() statements or Python debuggers are of limited use. But we still have ways to look closer.
Python's dis module can help us break down Python code into the internal instructions (bytecode) that the CPython interpreter sees. That can be very helpful for understanding how Python code works. Reading disassembled output can be tricky at first, but you don't need to understand every detail to spot differences between two pieces of code.
So let's look at some bytecode for these two comparisons. And if this is your first time looking at disassembled Python code, don't panic! Focus on how much longer the first block of instructions is:
>>> import dis >>> dis.dis('3 < 1 == False') 1 0 LOAD_CONST 0 (3) 2 LOAD_CONST 1 (1) 4 DUP_TOP 6 ROT_THREE 8 COMPARE_OP 0 (<) 10 JUMP_IF_FALSE_OR_POP 18 12 LOAD_CONST 2 (False) 14 COMPARE_OP 2 (==) 16 RETURN_VALUE >> 18 ROT_TWO 20 POP_TOP 22 RETURN_VALUE >>> dis.dis('(3 < 1) == False') 1 0 LOAD_CONST 0 (3) 2 LOAD_CONST 1 (1) 4 COMPARE_OP 0 (<) 6 LOAD_CONST 2 (False) 8 COMPARE_OP 2 (==) 10 RETURN_VALUE
Those extra instructions in the first block are the work Python has to do to manage chained comparisons. Have some fun playing with
dis - send it some code you understand, or some that you don't (yet)!
Here are some homespun animations that loop through the bytecode instructions, showing the evaluation stack along the way. If you want to follow along with a reference, this section of the
dis documentation explains how each bytecode instruction interacts with the evaluation stack.
Here's the breakdown of
3 < 1 == False (full size):
(3 < 1) == False (full size):
That was a lot of words and pictures to break down two comparison operations, but I hope you had fun along the way.
One tricky aspect of this question is that
< have the same precedence. Often this isn't relevant, because you would be unlikely to type:
if a < b == False: ...
when you could use the simpler:
if a >= b: ...
if not a < b: ...
< have higher precedence than equality checks like
==. That makes
3 < 1 == false functionally equivalent to
(3 < 1) == false. Rust sidesteps this confusion entirely by forcing you to be explicit:
Parentheses are required when chaining comparison operators. For example, the expression a == b == c is invalid and may be written as (a == b) == c.
The thing I hope people take away from this post is that if you're not sure what a line of Python code is doing, try disassembling it. It can't hurt, and it might lead to some fun discoveries.
The post that inspired me to pull out the
dis module more often was:
Weird Python Integers Part II: Constants in Bytecode by Kate Murphy
Thanks for reading! Please leave any questions or comments below, especially if you know of a better way to create evaluation stack animations from Python bytecode.
Keep calm and code in Python!