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Hello๐,
*My name is Alex and I'm maker of Devmates.co. ๐
We are resolving daily coding problems which asked by top tech companies together. We share our solutions, give some help if anyone stuck, support each other and just hangout together in the internet. ๐ปโ๏ธ๐ฌ
I get this problem from our members or just searching them in the internet(leetcode forums, Glassdoor, teamblind, etc.). Sometimes this problem can be very easy, sometimes too ๐ทโโ๏ธhard, everything depends on skills but we are trying to resolve all of them and Have Fun. ๐
Today I want to share problem which was asked by ๐ฆ Goldman Sachs.
Problem:
Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M
For example, 2 is written as II in Roman numeral, just two one's added together. 12 is written as, XII, which is simply X + II. The number 27 is written as XXVII, which is XX + V + II.
Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:
- I can be placed before V (5) and X (10) to make 4 and 9.
- X can be placed before L (50) and C (100) to make 40 and 90.
- C can be placed before D (500) and M (1000) to make 400 and 900.
Given a Roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.
Example:
Input: "III"
Output: 3
Input: "IX"
Output: 9
Input: "LVIII"
Output: 58
Input: "MCMXCIV"
Output: 1994
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