### Description:

Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements.

Return a list of pairs in ascending order(with respect to pairs), each pair [a, b] follows

a, b are from arr

a < b

b - a equals to the minimum absolute difference of any two elements in arr

### Solution:

Time Complexity : O(n)

Space Complexity: O(n)

```
var minimumAbsDifference = function(arr) {
const ans = [];
// Put smallest numbers first
arr.sort((a, b) => a - b);
// minDiff should be changed on the first iteration
let minDiff = Infinity;
for (let i = 1; i < arr.length; i++) {
// The new minDiff changes if the current diff is smaller
minDiff = Math.min(minDiff, arr[i] - arr[i - 1]);
}
for (let i = 1; i < arr.length; i++) {
// Push all pairs that equal the minDiff into ans
if (arr[i] - arr[i - 1] === minDiff) ans.push([arr[i - 1], arr[i]]);
}
return ans;
};
```

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