### Description:

Given an m x n binary matrix filled with 0's and 1's, find the largest square containing only 1's and return its area.

### Solution:

Time Complexity : O(n^2)

Space Complexity: O(n^2)

```
var maximalSquare = function(matrix) {
const rows = matrix.length, cols = rows > 0 ? matrix[0].length : 0;
// Create dp array
const dp = Array(rows + 1).fill(0).map(() => Array(cols + 1).fill(0));
// Keep trac of the max square length
let maxsqlen = 0;
for (let i = 1; i <= rows; i++) {
for (let j = 1; j <= cols; j++) {
// Only check cells that have a 1 in the original array
if (matrix[i-1][j-1] == '1'){
// Check if the current cell is part of a square
dp[i][j] = Math.min(Math.min(dp[i][j - 1], dp[i - 1][j]), dp[i - 1][j - 1]) + 1;
maxsqlen = Math.max(maxsqlen, dp[i][j]);
}
}
}
// Return the area of the square
return maxsqlen * maxsqlen;
};
```

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