LeetCode 96. Unique Binary Search Trees (javascript solution)

Description:

Given an integer n, return the number of structurally unique BST's (binary search trees) which has exactly n nodes of unique values from 1 to n.

Solution:

Time Complexity : O(n^2)
Space Complexity: O(n)

var numTrees = function(n) {
    // Create dp array
    let dp = new Array(n+1).fill(0);
    // Set base cases
    dp[0] = 1;
    dp[1] = 1;

    // dp[i] represents each subtree (left and right) of the root node
    for (let i = 2; i <= n; i++) {
        for (let j = 0; j < i; j++) {
            // dp[j] is the left side and dp[i-j-1] is the right side
            // Example: n = 2
            // i = 2 & j = 0, there are 2 nodes, nodes on left of root = j = 0 and nodes on right of root = 2 - j (because we are using j nodes on the left) - 1 (1 to account for the root node itself), dp[i] += dp[0] * dp[1] = 1 * 1 = 1 
            // Final iteration dp[2] += dp[1] * dp[0] = 2
            dp[i] += dp[j] * dp[i-j-1];
        }
    }
    return dp[n];
}