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David Bell

Posted on • Originally published at davidbell.space

# A Quick Look at the sort() Array Method in JavaScript

`````` (╯°□°)╯ .sort()
``````

The Array method `sort()` is handy for ordering Arrays and Objects.

## Simple use

For simple use you can just call `sort()` on an array.

Let’s say we have an array of numbers that we want sorting from low too high.

``````const nums = [5, 2, 1, 3, 4]

const numOrder = nums.sort()
// [1,2,3,4,5]
``````

Or is you have an array of strings we want sorting alphabetically.

``````const phonetics = ["zulu", "foxtrot", "charlie", "alpha"]
const orderPhonetics = phonetics.sort()
// [ 'alpha', 'charlie', 'foxtrot', 'zulu' ]
``````

## Sorting Values from Objects

We have an object of dogs:

``````const dogs = [
{ name: "bob", age: 3 },
{ name: "winston", age: 10 },
{ name: "spike", age: 5 },
]
``````

Let’s say we want to sort the dogs by youngest to oldest:

``````const ageOrder = dogs.sort((a, b) => {
if (a.name > b.name) {
return 1;
}

if (a.name < b.name) {
return -1;
}
return 0;
})

/* [ { name: 'bob', age: 3 },
{ name: 'spike', age: 5 },
{ name: 'winston', age: 10 } ]*/
``````

We pass in two arguments to `sort()` and using a ternerary operator we bubble sort the dogs by age. “Is a.age greater than b.age? If it is +1. If it is lower -1”.

Works the same when sorting alphabetically:

``````const alphaOrder = dogs.sort((a,b) => {
if (a.name > b.name) {
return 1
}
if (a.name < b.name) {
return -1
}
return 0
})
/* [ { name: 'bob', age: 3 },
{ name: 'spike', age: 5 },
{ name: 'winston', age: 10 } ] */
``````

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