Problem Link
Detailed Step-by-Step Explanation
https://leetcode.com/problems/3sum/solutions/7456672/most-optimal-solution-ever-pointers-beat-lyku
Solution
class Solution {
public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> ans = new ArrayList<>();
int n = nums.length;
Arrays.sort(nums);
for (int i = 0; i < n; i++) {
// Skip duplicate first elements
if (i != 0 && nums[i] == nums[i - 1]) continue;
int j = i + 1;
int k = n - 1;
while (j < k) {
int sum = nums[i] + nums[j] + nums[k];
if (sum < 0) {
j++;
} else if (sum > 0) {
k--;
} else {
ans.add(Arrays.asList(nums[i], nums[j], nums[k]));
j++;
k--;
// Skip duplicate second elements
while (j < k && nums[j] == nums[j - 1]) j++;
// Skip duplicate third elements
while (j < k && nums[k] == nums[k + 1]) k--;
}
}
}
return ans;
}
}

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