## level of challenge = 2/10

### Middle letter

- Write a function named mid that takes a string as its parameter.
- Your function should extract and return the middle letter.
- If there is no middle letter, your function should return the empty string.
- For example, mid("abc") should return "b" and mid("aaaa") should return "".

Hint

- First check if the string's length is even, and if so, return "".
- You can use the % (modulo) operator to check.
- An even string's length modulo 2 is 0, while an odd string's length modulo 2 is 1.
- You can google "python check if number is even or odd" for clarification.
- Also, note that in Python, an index must be an integer, not a floating-point number. So 2 is a valid index, but 2.0 is not.
- Therefore use integer division // to calculate the index, or cast the float to an integer with int().

#### My solution

```
def mid(my_string):
length = len(my_string) % 2
if length == 0:
return ""
elif length != 0:
middle = len(my_string) // 2
return my_string[middle]
print(mid("cars"))
```

#### The another solution

- this approach uses // which is integer division in Python 3
- alternatively, use / and int() in combination.

```
def middel(string):
if len(string) % 2 == 0:
return ""
return string[len(string)//2]
print(middel("abc"))
```

Add your solution in the comment :)

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