Python Exercise 16: find the highest index alphabet

Question

• Given a name, return the letter with the highest index in alphabetical order,
  • with its corresponding index,
  • in the form of a string.
• You are prohibited to use max() nor is reassigning a value to the alphabet list allowed.

Example

alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]


alphabet_index(alphabet, "Flavio") ➞ "22v"

alphabet_index(alphabet, "Andrey") ➞ "25y"

alphabet_index(alphabet, "Oscar") ➞ "19s"

My attempt

• algorithm

>find the letter with the highest index in alphabetical order
 initialise highest_index to 0
 initialise highest_index_character to empty string
>>Find the highest index of the character and the relevant character in the name
  initialise highest_index to 0
  initialise highest_index_character to empty string
  for each character in the name:
      if character's index in alphabet is higher than in highest_index
      set highest_index to character's index
      set highest_index_character to character
  return string of highest_index and highest_index_character

• code

alphabet = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u",  
            "v", "w", "x", "y", "z"]  


def alphabet_index(alphabet: list, name: str):
    # The name are in upper case, but alphabet is in lower case
    name = name.lower()  
    # initialise highest_index to 0  
    highest_index = 0  
    # initialise highest_index_character to empty string  
    highest_index_character = str()  
    # for each character in the name:  
    for character in name:  
        #  if character's index in alphabet is higher than in highest_index  
        if alphabet.index(character) + 1 > highest_index:  
            # set highest_index to character's index  
            highest_index = alphabet.index(character) + 1  
            #   set highest_index_character to character  
            highest_index_character = character  
    # return string of highest_index and highest_index_character  
    return str(str(highest_index) + highest_index_character)  

Other solution

• don't find any particular impressive code. If there is shorter way to do this, please let me know.

My reflection

• This takes me long time to write out the algorithm in appropriate formate, need to practice more

Credit

• challenge find on edabit