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Select all nodes in a DOM except the nth query

Musale Martin
Python | GO | JavaScript
・1 min read

Say you have a HTML structure like this one:

<body>
    <div>
        <span style="font-weight:bold;">More Lorem Ipsum text: </span>
        <span>And More Lorem Ipsum text</span>
        <span>Some More Lorem Ipsum text</span>
        <span>Get Some More Lorem Ipsum text</span>
        <span>Finally Some More Lorem Ipsum text</span> In conclusion.
    </div>
</body>
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I would like to apply some styling to the first span and then I change the remaining spans into text nodes.

The challenge I had was figuring out how to get the rest of the spans after the first. Turns out, it's quite simple:

const spans = document.querySelectorAll("span:not(:nth-child(1))")
spans.forEach(span => {
    const spanTxt = span?.textContent;
    if (spanTxt) span.replaceWith(spanTxt.trim())
})
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That JavaScript (TypeScript) code will result to:

<body>
    <div>
        <span style="font-weight:bold;">More Lorem Ipsum text:</span> And More Lorem Ipsum text Some More Lorem Ipsum text Get Some More Lorem Ipsum text Finally Some More Lorem Ipsum text In conclusion.
    </div>
</body>
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